Spotify logo using python turtle

import turtle as t

t.Screen().bgcolor("Black")

t.speed(15)

t.begin_fill()

t.fillcolor('#1DB954')

t.pencolor("#1DB954")

t.pensize(0)

t.circle(100)

t.end_fill()

t.penup()

t.goto(40,50)

t.pendown()

t.left(150)

t.forward(0)

t.pensize(15)

t.pencolor('black')

t.circle(80,60)

t.penup()

t.goto(50,85)

t.pendown()

t.pensize(17)

t.right(60)

t.forward(0)

t.circle(100,60)

t.penup()

t.goto(60,120)

t.pendown()

t.pensize(20)

t.right(60)

t.forward(0)

t.circle(120,60)

t.penup()

t.goto(130, 55)

t.pendown()

t.color("#1DB954")

t.write("Spotify", font=("Arial", 60, "bold"))

t.done()

FB logo using turtle

from turtle import *

speed(10)

color("#0270d6")

Screen().bgcolor('black')

penup()

goto(0, 150)

pendown()

begin_fill()

forward(150)

circle(-50, 90)

forward(300)

circle(-50, 90)

forward(300)

circle(-50, 90)

forward(300)

circle(-50, 90)

forward(150)

end_fill()

color("white")

penup()

goto(140, 80)

pendown()

begin_fill()

right(180)

forward(50)

circle(80, 90)

forward(50)

right(90)

forward(80)

left(90)

forward(40)

left(90)

forward(80)

right(90)

forward(160)

left(90)

forward(55)

left(90)

forward(160)

right(90)

forward(70)

left(80)

forward(45)

left(100)

forward(80)

right(90)

forward(40)

circle(-40, 90)

forward(40)

left(90)

forward(45)

end_fill()

hideturtle()

done()

Check if the characters in a string form a Palindrome in O(1) extra space

def firstPos(str, start, end):

firstChar = -1

for i in range(start, end + 1):

if (str[i] >= 'a' and str[i] <= 'z') :

firstChar = i

break

return firstChar

def lastPos(str, start, end):

lastChar = -1

for i in range(start, end - 1, -1) :

if (str[i] >= 'a' and str[i] <= 'z') :

lastChar = i

break

return lastChar

def isPalindrome(str):

firstChar = 0

lastChar = len(str) - 1

ch = True

for i in range(len(str)) :

firstChar = firstPos(str, firstChar, lastChar);

lastChar = lastPos(str, lastChar, firstChar);

if (lastChar < 0 or firstChar < 0):

break

if (str[firstChar] == str[lastChar]):

firstChar += 1

lastChar -= 1

continue

ch = False

break

return (ch)

if __name__ == "__main__":

str = "m a 343 la y a l am"

if (isPalindrome(str)):

print("YES")

else:

print("NO")

 

program to print all Prime numbers in an Interval

def prime(x, y):

prime_list = []

for i in range(x, y):

if i == 0 or i == 1:

continue

else:

for j in range(2, int(i/2)+1):

if i % j == 0:

break

else:

prime_list.append(i)

return prime_list

starting_range = 2

ending_range = 7

lst = prime(starting_range, ending_range)

if len(lst) == 0:

print("There are no prime numbers in this range")

else:

print("The prime numbers in this range are: ", lst)

Program for compound interest

def compound_interest(principle, rate, time):

Amount = principle * (pow((1 + rate / 100), time))

CI = Amount - principle

print("Compound interest is", CI)

compound_interest(10000, 10.25, 5)