Write a python code to print this pattern.

 

def pattern(n):

num = 65

for i in range(0,n):

for j in range(0,i+1):

ch = chr(num)

print(ch,end = " ")

num = num + 1

print("\r")

n = 5

pattern(n)

Create a stopwatch using python

import tkinter as Tkinter

from datetime import datetime

counter = 66600

running = False

def counter_label(label):

def count():

if running:

global counter

if counter==66600:

display="Starting..."

else:

tt = datetime.fromtimestamp(counter)

string = tt.strftime("%H:%M:%S")

display=string

label['text']=display 

label.after(1000, count)

counter += 1

count()

def Start(label):

global running

running=True

counter_label(label)

start['state']='disabled'

stop['state']='normal'

reset['state']='normal'

def Stop():

global running

start['state']='normal'

stop['state']='disabled'

reset['state']='normal'

running = False

def Reset(label):

global counter

counter=66600

if running==False:

reset['state']='disabled'

label['text']='Welcome!'

else:

label['text']='Starting...'

root = Tkinter.Tk()

root.title("Stopwatch")

root.minsize(width=250, height=70)

label = Tkinter.Label(root, text="Welcome!", fg="black", font="Verdana 30 bold")

label.pack()

f = Tkinter.Frame(root)

start = Tkinter.Button(f, text='Start', width=6, command=lambda:Start(label))

stop = Tkinter.Button(f, text='Stop',width=6,state='disabled', command=Stop)

reset = Tkinter.Button(f, text='Reset',width=6, state='disabled', command=lambda:Reset(label))

f.pack(anchor = 'center',pady=5)

start.pack(side="left")

stop.pack(side ="left")

reset.pack(side="left")

root.mainloop()

program to find number of days between two given dates

class Date:

def __init__(self, d, m, y):

self.d = d

self.m = m

self.y = y

monthDays = [31, 28, 31, 30, 31, 30,

31, 31, 30, 31, 30, 31]

def countLeapYears(d):

years = d.y

if (d.m <= 2):

years -= 1

return int(years / 4) - int(years / 100) + int(years / 400)

def getDifference(dt1, dt2):

n1 = dt1.y * 365 + dt1.d

for i in range(0, dt1.m - 1):

n1 += monthDays[i]

n1 += countLeapYears(dt1)

n2 = dt2.y * 365 + dt2.d

for i in range(0, dt2.m - 1):

n2 += monthDays[i]

n2 += countLeapYears(dt2)

return (n2 - n1)

dt1 = Date(13, 12, 2018)

dt2 = Date(25, 2, 2019)

print(getDifference(dt1, dt2), "days")

Program to convert DateTime to string

import time

def convert(datetime_str):

datetime_str = time.mktime(datetime_str)

format = "%b %d %Y %r" 

dateTime = time.strftime(format, time.gmtime(datetime_str))

return dateTime

date_time = (2018, 12, 4, 10, 7, 00, 1, 48, 0)

print(convert(date_time))

program to find Tuples with positive elements in List of tuples

test_list = [(4, 5, 9), (-3, 2, 3), (-3, 5, 6), (4, 6)]

print("The original list is : " + str(test_list))

res = [sub for sub in test_list if all(ele >= 0 for ele in sub)]

print("Positive elements Tuples : " + str(res))